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Equation of curve

Equations of curve evaluate by doing integration of derivative curve. The gradient and a point the curve passes through are given as.. Gradient: dy/dx = 6sqrt(x) Point the curve passes through: (4,1) I need to find the equation of the curve. Therefore integration is process of finding equation of the curve. Equation of curve

Integration by Substitution-4

This post is about worksheet of integration by substitutions.  It also one of most important concept of integral calculus .  The function ƒ(φ(t))φ′(t) is also integrable on [a,b] integration by substitution

 
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