This post is about worksheet of Integration by trigonometric substitution. It also one of most important concept of integral calculus . The function ƒ(φ(t))φ′(t) is also integrable on [a,b] Integration by substitution
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Category: Pure Maths
Volume -2
To get a solids of revolution we start out with a function, y=f (x), on an interval [a,b]. We then rotate this curve about a given axis to get the surface of the solid of revolution. Volume
Volume
To get a solid of revolution we start out with a function, y=f (x), on an interval [a,b]. We then rotate this curve about a given axis to get the surface of the solid of revolution. volume of revolution
Integration by substitution
This post is about worksheet of integration by trigonometric substitution. It also one of most important concept of integral calculus . The function ƒ(φ(t))φ′(t) is also integrable on [a,b] Integration by trigonometric substitutions
Expansion
Expansions of Algebraic Expressions The formula: a(b+c) = ab + ac Algebraic Expansion. (a+b)(c+d)=ac+ad+bc+bd and (a+b)(a-b)= a ² – b² difference of square (a+b)² = a² + 2ab + b² perfect square (a-b) ²=a²-2ab+b² Expansion
Factorisation
Factorisation process we applied bracket to take common term out. Also we apply difference of square of variable. Hence we reduce no of terms in expression. Therefore factorisation and expansion are reverse process. Factorisation
Differential Eq
Differential Equation is a function and one or more of its derivatives. Hence it solve by variable seperable and linear differential eq method. Also it solve by homogeneous. Differential Equation
Logarithmic Expression
Solve the logarithmic equation. This problem involves the use of the symbol “ln” instead of “log” to mean logarithm. Logarithmic expression
Complex Number
Conversion from Polar to Rectangular Form Complex and vice versa. r cos Θ = x , r sin Θ = y Conversion of polar to Rectangular
Logarthmic Equation
Logarithms equation can be solved using the properties of logarithms. So equation either are solve by log or exponent. Because both inverse of each other hence are either way exponent or log.In both apply properties of log or exponent. Also we need to factorised to solve. Logarithmic eq
